Advertisements
Advertisements
प्रश्न
Find the area of a triangle whose base is 3.8 cm and height is 2.8 cm.
उत्तर
Base of a triangle = 3.8cm
Height of a triangle = 2.8cm
Area of a triangle
= `(1)/(2) xx "Base" xx "Height"`
= `(1)/(2) xx 3.8 xx 2.8`
= 5.32cm2.
APPEARS IN
संबंधित प्रश्न
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90o. Find the area of quadrilateral ABOC.
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height.
The given figure shows a right-angled triangle ABC and an equilateral triangle BCD. Find the area of the shaded portion.
The lengths of the sides of a triangle are in the ratio 4: 5 : 3 and its perimeter is 96 cm. Find its area.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.
Find the area of a triangle whose sides are 27 cm, 45 cm and 36 cm.
The perimeter of a triangle is 72cm and its sides are in the ratio 3:4:5. Find its area and the length of the altitude corresponding to the longest side.
Find the perimeter of An isosceles triangle with equal sides 10 cm each and third side is 7 cm
Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.