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प्रश्न
Find the Cartesian equation of the circle whose parametric equations are x = 3 cos θ, y = 3 sin θ, 0 ≤ θ ≤ 2π.
उत्तर
Given x = 3 cos θ, y = 3 sin θ
Now x2 + y2 = 9 cos2θ + 9 sin2θ
x2 + y2 = 9 (cos2θ + sin2θ)
x2 + y2 = 9 which is the Cartesian equation of the required circle.
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