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प्रश्न
Find the de Broglie wavelength of electrons moving with a speed of 7 × 106 ms -1.
उत्तर
λ = de-Broglie wavelength, v = 7 × 106 ms -1
⇒ `lambda = h/p =h/(mv)`
`= (6.6xx10^-34)/(9.1xx10^-31 xx7xx10^6)`m
`lambda = (66xx10^-9)/(91xx7)`
`lambda = 0.1 xx 10^-9`m
`lambda` = 0.1 nm
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