हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Find the equation of a line through the given pair of point (2, 3) and (– 7, – 1) - Mathematics

Advertisements
Advertisements

प्रश्न

Find the equation of a line through the given pair of point (2, 3) and (– 7, – 1)

योग

उत्तर

Equation of the line joining the point  (2, 3) and (– 7, – 1) is

`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`

`(y - 3)/(-1 - 3) = (x - 2)/(-7 - 2)`

⇒ `(y - 3)/(-4) = (x - 2)/(-9)`

– 9 (y – 3) = – 4 (x – 2)

– 9y + 27 = – 4x + 8

4x – 9y + 27 – 8 = 0

4x – 9y + 19 = 0

The required equation is 4x – 9y + 19 = 0

shaalaa.com
Straight Line
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Coordinate Geometry - Exercise 5.3 [पृष्ठ २३०]

APPEARS IN

सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 5 Coordinate Geometry
Exercise 5.3 | Q 7. (ii) | पृष्ठ २३०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×