हिंदी

Find the equation of the circle with centre (–2, 3) and radius 4 - Mathematics

Advertisements
Advertisements

प्रश्न

Find the equation of the circle with centre (–2, 3) and radius 4

योग

उत्तर

The equation of a circle with centre (h, k) and radius r is given as

(x­ – h)2 + (y ­– k)2 = r2

It is given that centre (h, k) = (–2, 3) and radius (r) = 4.

Therefore, the equation of the circle is

(x + 2)2 + (y – 3)2 = (4)2

x2 + 4x + 4 + y2 – 6y + 9 = 16

x2 + y2 + 4x – 6y – 3 = 0

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Conic Sections - Exercise 11.1 [पृष्ठ २४१]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise 11.1 | Q 2 | पृष्ठ २४१
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×