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प्रश्न
Find the excess of 4m2 + 4n2 + 4p2 over m2+ 3n2 – 5p2
योग
उत्तर
The required result will be by substracting
m2+ 3n2 – 5p2 from 4m2 + 4n2 + 4p2
= 4m2 + 4n2 + 4p2 - (m2 + 3n2 - 5p2)
= 4m2 + 4n2 + 4p2 - m2 - 3n2 - 5p2
= 4m2 - m2 + 4n2 - 3n2 + 4p2 + 5p2
= 3m2 + n2 + 9p2
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