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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Find the G.C.D. of the given polynomials x4 + 3x3 – x – 3, x3 + x2 – 5x + 3 - Mathematics

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प्रश्न

Find the G.C.D. of the given polynomials

x4 + 3x3 – x – 3, x3 + x2 – 5x + 3

योग

उत्तर

p(x) = x+ 3x3 – x – 3

g(x) = x3 + x2 – 5x + 3


3x2 + 6x – 9 = 3(x2 + 2x – 3)

Now dividing g(x) = x3 + x2 – 5x + 3

by the new remainder ...(leaving the constant 3)

we get x2 + 2x – 3

G.C.F. = x2 + 2x – 3

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GCD and LCM of Polynomials
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अध्याय 3: Algebra - Exercise 3.2 [पृष्ठ ९६]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.2 | Q 1. (i) | पृष्ठ ९६
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