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प्रश्न
Find the order and degree of the differential equation `(1 + 3 dy/dx)^(2/3) = 4((d^3y)/(dx^3))`.
योग
उत्तर
`(1 + (3dy)/dx)^(2/3) = 4((d^3y)/(dx^3))`
Cubing both sides
`(1 + (3dy)/dx)^2 = 64((d^3y)/(dx^3))^3`
∴ Order = 3,
Degree = 3
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