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Find the slope of tangent to the curve x = sin θ and y = cos 2θ at θ = π6 - Mathematics and Statistics

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प्रश्न

Find the slope of tangent to the curve x = sin θ and y = cos 2θ at θ = `pi/6`

योग

उत्तर

Given, x = sin θ and y = cos 2θ

Differentiating w.r.t. θ, we get

`("d"x)/("d"theta)` = cos θ and `("d"y)/("d"theta)` = – 2sin 2θ

∴ `("d"y)/("d"x) = ((("d"y)/("d"theta)))/((("d"x)/("d"theta))) = (-2sin2theta)/(cos theta)`

Slope of the tangent at θ = `pi/6` is

`(("d"y)/("d"x))_(theta = pi/6) = (-2sin2(pi/6))/(cos(pi/6))`

= `(-2sin(pi/3))/(cos(pi/6))`

= `(-2 xx sqrt(3)/2)/(sqrt(3)/2)`

= – 2

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Applications of Derivatives in Geometry
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2.2: Applications of Derivatives - Short Answers I

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