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प्रश्न
Find the smallest number which, when divided by 12, 15, 18, 24 and 36 leaves no remainder
उत्तर
The least number which is exactly divisible by each given number is their L.C.M. Required number L.C.M. of 12, 15, 18, 24 and 36.
| 2 | 12, | 15, | 18, | 24, | 36 |
| 2 | 6, | 15, | 9, | 12, | 18 |
| 3 | 3, | 15, | 9, | 6, | 9 |
| 3 | 1, | 5, | 3, | 2, | 3 |
| 1, | 5, | 1, | 2, | 1 |
∴ L.C.M. = Least required number
= 2 x 2 x 3 x 3 x 5 x 2 = 360
Hence, the least required number = 360
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