Advertisements
Advertisements
प्रश्न
Find the smallest value of x for which `5 - 2x < 5 1/2 - 5/3x`, where x is an integer.
उत्तर
`5 - 2x < 5 1/2 - 5/3x`
`-2x + 5/3x< 11/2 - 5`
`(-x)/3 < 1/2`
`-x < 3/2`
`x > (-3)/2`
x > –1.5
Thus, the required smallest value of x is –1.
APPEARS IN
संबंधित प्रश्न
`-5x >= 15 => x >= -3`
If a > b, then a + c > b + c
If a > b, then `a/c < b/c`
Solve the inequation:
3 – 2x ≥ x – 12 given that x ∈ N.
Solve the inequation:
`12 + 1 5/6 x ≤ 5 + 3x` and `x in R`.
Solve for x in the following in-equation, if the replacement set is R;
x + 7 ≥ 15 + 3x
Solve for x in the following in-equation, if the replacement set is R;
9 - 4x ≤ 15 - 7x
Solve the given inequation and graph the solution on the number line
2y - 3
For each inequality, determine which of the given numbers are in the solution set:
16 - 5 x ≤ - 4; 4, -3, 10.
Find the solution set of the following inequalities and draw the graph of their solutions sets:
`(3)/|x - 2| > 5`.