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प्रश्न
Find the sum of:
−312, 39 and 192
योग
उत्तर
(–312) + (+39) + (+192)
= (–231) + (–81) + (+39) + (+192)
= (–231) + (–81) + (+231)
= (–231) + (+231) + (–81)
= 0 + (–81) ...[∵ (–a) + (a) = 0]
= –81
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