Advertisements
Advertisements
प्रश्न
Find the third proportional to a – b and a2 – b2
उत्तर
Let the third proportional to a – b and a2 – b2 be x.
`=>` a – b, a2 – b2, x are in continued proportion.
`=>` a – b : a2 – b2 = a2 – b2 : x
`=> (a - b)/(a^2 - b^2) = (a^2 - b^2)/x`
`=> x = (a^2 - b^2)^2/(a - b)`
`=> x = ((a + b)(a - b)(a^2 - b^2))/(a - b)`
`=>` x = (a + b)(a2 – b2)
APPEARS IN
संबंधित प्रश्न
Using properties of proportion, solve for x. Given that x is positive:
`(2x + sqrt(4x^2 -1))/(2x - sqrt(4x^2 - 1)) = 4`
If a, b, c and d are in proportion prove that `sqrt((4a^2 + 9b^2)/(4c^2 + 9d^2)) = ((xa^3 - 4yb^3)/(xc^3 - 5yd^3))^(1/3)`
If `x/a = y/b = z/c` prove that `(2x^3 - 3y^3 + 4z^3)/(2a^3 - 3b^3 + 4c^3) = ((2x - 3y + 4z)/(2a - 3b + 4c))^3`
If x and y be unequal and x : y is the duplicate ratio of x + z and y + z, prove that z is mean proportional between x and y.
Check whether the following numbers are in continued proportion.
9, 12, 16
Find the third proportional to 5, 10
What number must be added to each of the numbers 15, 17, 34 and 38 to make them proportional?
If 7 : 5 is in proportion to x : 25, then ‘x’ is
Find the missing number in the box in the proportions:
`16/36 = square/63 = 36/square = square/117`
Determine if the following are in proportion.
4, 6, 8, 12