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प्रश्न
Find the transformed equation of the straight line 2x – 3y + 5 = 0, when the origin is shifted to the point (3, –1) after translation of axes.
विकल्प
3X – 2Y + 14 = 0
3X – 2Y – 14 = 0
2X – 3Y + 14 = 0
2X – 3Y – 14 = 0
MCQ
उत्तर
2X – 3Y + 14 = 0
Explanation:
Let coordinates changes from (x, y) `rightarrow` (X, Y) in new coordinate system whose origin is h = 3, k = –1
∴ x = X + 3, y = Y – 1
So, 2x – 3y + 5 = 0
`\implies` 2 (X + 3) – 3 (Y – 1) + 5 = 0
`\implies` 2X + 6 – 3Y + 3 + 5 = 0
`\implies` 2X – 3Y + 14 = 0
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Straight Lines
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