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प्रश्न
Find the value of `{((-2)/3)^(-2)}^2`
योग
उत्तर
`{((-2)/3)^(-2)}^2` = `{(3/(-2))^2}^2` ...`(a^(-m) = 1/a^m)`
= `{3^2/(-2)^2}^2` ....`[(a/b)^m = a^m/b^m]`
= `{(-3/2)xx((-3)/2)}^2`
= `(9/4)^2`
= `9/4 xx 9/4`
= `81/16`
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