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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Find the value of 5 correct to 2 decimal places; then use it to find the square root of 3-53+5 correct to 2 significant digits. - Mathematics

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प्रश्न

Find the value of `sqrt5` correct to 2 decimal places; then use it to find the square root of `(3-sqrt(5))/(3+sqrt(5)` correct to 2 significant digits.

योग

उत्तर

`sqrt(5)` = 2.236 = 2.24

  2.236
2 5.000000
4
42 100
84
443 1600
1329
4466 27100
26796
  304

 

 

 

 

 

 

 

 

 

 

`(3-sqrt(5))/(3+sqrt(5)`

= `sqrt(((3-sqrt(5))((3-sqrt(5))))/((3+sqrt(5))(3-sqrt(5))`

= `sqrt(((3-sqrt(5))^2)/((3)^2 - sqrt((5))^2)`

= `sqrt((3-sqrt5)^2)/(9-5)`

= `sqrt((3-sqrt(5)^2)/(4)`

= `((3-2.24))/(2)`

= `((0.76))/(2)`

= 0.38

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Squares and Square Root - Exercise 3 (B) [पृष्ठ ४२]

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सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 3 Squares and Square Root
Exercise 3 (B) | Q 8 | पृष्ठ ४२
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