Question

Find the value of a when x = 3 is a solution set of ax² + (a - 4)x + 1 = a.

Answer 1

Given x = 3 is a solution of ax² + (a - 4)x + 1 = a
⇒ x = 3 must satisfy the equation.
⇒ 9a + (a - 4)3 + 1 - a = 0
⇒ 9a + 3a - 12 + 1 - a = 0
⇒ 11a - 11 = 0
⇒ a = 1.