Advertisements
Advertisements
प्रश्न
Find the values of k so that the sum of tire roots of the quadratic equation is equal to the product of the roots in each of the following:
kx2 + 2x + 3k = 0
उत्तर
kx2 + 2x + 3k = 0.
Here, a = k, b = 2, and c = 3k.
Sum of roots = `-b/a = -(2)/k`
Product of root = `c/a`
= `(3k)/k`
= 3
Sum of roots = Product of roots
`-(2)/k = 3`
⇒ 3k = -2
⇒ k = `-(2)/(3)`.
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the quadratic equation (3k + 1) x2 + 2(k + 1) x + 1 = 0 has equal roots. Also, find the roots.
Without solving, examine the nature of roots of the equation x2 – 5x – 2 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
x2 - kx + 9 = 0
Solve the following quadratic equation using formula method only
`sqrt 3 "x"^2 + 10 "x" - 8 sqrt 3 = 0`
Solve the following quadratic equation using formula method only
3a2x2 +8abx + 4b2 = 0, a ≠ 0
48x² – 13x -1 = 0
Find the discriminant of the following equations and hence find the nature of roots: 7x2 + 8x + 2 = 0
Find the discriminant of the following equations and hence find the nature of roots: 3x2 + 2x - 1 = 0
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
The value of 'a' for which the sum of the squares of the roots of 2x2 – 2(a – 2)x – a – 1 = 0 is least is ______.