Advertisements
Advertisements
рдкреНрд░рд╢реНрди
Find the two consecutive natural numbers whose product is 20.
рдЙрддреНрддрд░
Let the two consecutive natural numbers be ‘x’ and ‘x + 2’
⇒ Given that the product of the natural numbers is 20
Hence ⇒ x(x + 1) = 20
⇒ ЁЭСе2 + ЁЭСе = 20
⇒ ЁЭСе2 + ЁЭСе - 20 = 0
⇒ ЁЭСе2 + 5ЁЭСе - 4ЁЭСе - 20 = 0
⇒ ЁЭСе(ЁЭСе + 5) - 4(ЁЭСе + 5) = 0
⇒ ЁЭСе = -5 ЁЭСЬЁЭСЯ ЁЭСе = 4
Considering positive value of x as x ∈ N
For r = 4, x + 1 = 4 + 1 = 5
∴ The two consecutive natural numbers are 4 as 5.
APPEARS IN
рд╕рдВрдмрдВрдзрд┐рдд рдкреНрд░рд╢реНрди
Find the roots of the following quadratic equation by factorisation:
100x2 – 20x + 1 = 0
Solve the following quadratic equations by factorization:
a(x2 + 1) - x(a2 + 1) = 0
The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed per hour in each direction?
The sum of two natural number is 28 and their product is 192. Find the numbers.
Find two consecutive multiples of 3 whose product is 648.
The difference of two natural numbers is 5 and the difference of heir reciprocals is `5/14`Find the numbers
Show that x = −2 is a solution of 3x2 + 13x + 14 = 0.
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
Let тИЖ ABC тИ╜ тИЖ DEF and their areas be respectively, 64 cm2 and 121 cm2. If EF = 15⋅4 cm, find BC.
Solve the equation:
`6(x^2 + (1)/x^2) -25 (x - 1/x) + 12 = 0`.