Advertisements
Advertisements
प्रश्न
Find two consecutive positive odd numbers, the sum of whose squares is 74.
उत्तर
Let the consecutive positive odd numbers be x and x + 2.
From the given information,
x2 + (x + 2)2 = 74
2x2 + 4x + 4 = 74
2x2 + 4x – 70 = 0
x2 + 2x – 35 = 0
(x + 7)(x – 5) = 0
x = –7, 5
Since, the numbers are positive, so, x = 5.
Thus, the numbers are 5 and 7.
APPEARS IN
संबंधित प्रश्न
A positive number is divided into two parts such that the sum of the squares of the two parts is 20. The square of the larger part is 8 times the smaller part. Taking x as the smaller part of the two parts, find the number.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
The sum of the squares of two consecutive positive even numbers is 52. Find the numbers.
Three positive numbers are in the ratio `1/2 : 1/3 : 1/4`. Find the numbers if the sum of their squares is 244.
Divide 20 into two parts such that three times the square of one part exceeds the other part by 10.
Out of three consecutive positive integers, the middle number is p. If three times the square of the largest is greater than the sum of the squares of the other two numbers by 67; calculate the value of p.
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
Two integers differ by 2 and sum of their squares is 52. The integers are ______.
The difference between the digits of a two-digit number is 2 and the product of digits is 24. If tens digit is bigger, the number is ______.
The sum of two whole numbers is 18 and their product is 45, the numbers are ______.
