Question

Find X, If `[X - 5 - 1] [(1, 0, 2),(0, 2, 1),(2, 0, 3)][(x),(4),(1)] ` = 0

विकल्प

• `+- 4 sqrt(3)`

• `4sqrt(3)`

• `-4sqrt(3)`

• Zero

Answer 1

`+- 4 sqrt(3)`

Explanation:

Given, `[X - 5 - 1] [(1, 0, 2),(0, 2, 1),(2, 0, 3)][(x),(4),(1)] ` = 0

`[(x - 2 - 10, 2x - 8)][(x),(4),(1)]` = 0

⇒ `[x(x - 2) - 40 + 2x - 8]` = 0

⇒ `[x^2 - 2x - 40 + 2x - 8]` = 0

⇒ `[x^2 - 48] = [0] `

∴ `x^2 - 48` = 0

⇒ `x^2` = 48

⇒ `x = +- 4sqrt(3)`