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प्रश्न
Find x so that x + 6, x + 12 and x + 15 are consecutive terms of a Geometric Progression
उत्तर
G.P. = x + 6, x + 12, x + 15
In G.P. r = `("t"_2)/("t"_1) = ("t"_3)/("t"_2)`
`(x + 12)/(x + 6) = (x + 15)/(x + 12)`
(x + 12)2 = (x + 6) (x + 5)
x2 + 24x + 144 = x2 + 6x + 15x + 90
24x – 21x = 90 – 144
3x = – 54
x = `(-54)/3` = – 18
x = – 18
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