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प्रश्न
Find x, such that: `(-2)/3=6/"x"`
योग
उत्तर
`(-2)/3=6/"x"`
-2x = 6 × 3
x = `(6 xx 3)/-2 = -3 xx 3 = -9`
`therefore (-2)/3=6/-9 = - 6/9`
OR
`(-2)/3=6/"x"`
`=> (- 2 xx 3)/(- 3 xx 3) = 6/"x"`
`=> 6/-9 = 6/"x"`
⇒ x = - 9
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