Question

For a series LCR-circuit, the power loss at resonance is ______.

विकल्प

• I² R

• I² ω C

• `"V"^2/(omega "C")`

• `"V"^2/(omega "L" - 1//omega"C")`

Answer 1

For a series LCR-circuit, the power loss at resonance is I² R.

Explanation:

At resonance, the impedance of the circuit is equal to the resistance. Therefore,

P_av = I² R