हिंदी

For L.P.P. maximize z = 4x1 + 2x2 subject to 3x1 + 2x2 ≥ 9, x1 - x2 ≤ 3, x1 ≥ 0, x2 ≥ 0 has ______. -

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प्रश्न

For L.P.P. maximize z = 4x1 + 2x2 subject to 3x1 + 2x2 ≥ 9, x1 - x2 ≤ 3, x1 ≥ 0, x2 ≥ 0 has ______.

विकल्प

  • infinite number of optimal solutions

  • unbounded solution

  • no solution

  • one optimal solution

MCQ
रिक्त स्थान भरें

उत्तर

For L.P.P. maximize z = 4x1 + 2x2 subject to 3x1 + 2x2 ≥ 9, x1 - x2 ≤ 3, x1 ≥ 0, x2 ≥ 0 has unbounded solution.

Explanation:

We have, maximise z = 4x1 + 2x2 

Subject to constracts, 3x1 + 2x2 ≥ 9, x1 - x2 ≤ 3, x1 ≥ 0, x2 ≥ 0

On taking given constraints as equation, we get the following graphs

Here, we get feasible region Is unbounded.

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