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प्रश्न
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also, find the solution of the equation:
(m – 3)x2 – 4x + 1 = 0
उत्तर
(m – 3)x2 – 4x + 1 = 0
Here a = (m – 3), b = – 4 and c = 1
Given equation has equal roots
Then D = 0
`=>` b2 – 4ac = 0
`=>` (– 4)2 – 4(m – 3)(1) = 0
`=>` 16 – 4m + 12 = 0
`=>` – 4m = – 28
`=>` m = 7
Put value of m in given equation
4x2 – 4x + 1 = 0
`=>` (2x – 1)2 = 0
`=>` 2x – 1 = 0
`=> x = 1/2`
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