Advertisements
Advertisements
प्रश्न
For what value of x are the points A(-3, 12), B(7, 6) and C(x, 9) collinear.
उत्तर
A(-3,12) ,B (7,6) and C(x,9) are the given points. Then:
`(x_1=-3,y_1=12) , (x_2=7,y_2=6) and (x_3= x, y_3=9)`
It is given that points A, B and C are collinear. Therefore,
`x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)=0`
`⇒ (-3)(6-9)+7(9-12)+x(12-6)=0`
`⇒(-3)(-3)+7(-3)+x(6)=0`
`⇒ 9-21+6x=0`
`⇒ 6x-12=0`
`⇒ 6x =12`
`⇒ x = 12/6=12`
Therefore, when x =2 , the given points are collinear
APPEARS IN
संबंधित प्रश्न
Find equation of line joining (1, 2) and (3, 6) using the determinant.
Find the area of the following triangle:
Prove that (2, -2) (-2, 1) and (5, 2) are the vertices of a right-angled triangle. Find the area of the triangle and the length of the hypotenuse.
Find the value of k so that the area of the triangle with vertices A (k+1, 1), B(4, -3) and C(7, -k) is 6 square units
Find a relation between x and y, if the points A(2, 1), B(x, y) and C(7,5) are collinear.
Show that ∆ ABC with vertices A (–2, 0), B (0, 2) and C (2, 0) is similar to ∆ DEF with vertices D (–4, 0), F (4, 0) and E (0, 4) ?
In ☐ABCD, l(AB) = 13 cm, l(DC) = 9 cm, l(AD) = 8 cm, find the area of ☐ABCD.
A field is in the shape of a right angled triangle whose base is 25 m and height 20 m. Find the cost of levelling the field at the rate of ₹ 45 per sq.m2
If the co-ordinates of the vertices of an equilateral triangle with sides of length ‘a’ are (x1, y1), (x2, y2), (x3, y3), then `|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|^2 = (3"a"^4)/4`
Points A(–6, 10), B(–4, 6) and C(3, –8) are collinear such that AB = `2/9` AC.