Advertisements
Advertisements
प्रश्न
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
Slope of X-axis is ______.
विकल्प
1
−1
0
Cannot be determined
उत्तर
Slope of X-axis is 0.
Explanation:
The X-axis is horizontal, so its slope, which measures vertical change divided by horizontal change, is 0.
APPEARS IN
संबंधित प्रश्न
Find the slope of the line parallel to AB if : A = (0, −3) and B = (−2, 5)
The line passing through (0, 2) and (−3, −1) is parallel to the line passing through (−1, 5) and (4, a). Find a.
Find the value(s) of k so that PQ will be parallel to RS. Given : P(3, −1), Q(7, 11), R(−1, −1) and S(1, k)
Find the value(s) of k so that PQ will be parallel to RS. Given : P(5, −1), Q(6, 11), R(6, −4k) and S(7, k2)
If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.
Find the value of k for which the lines kx – 5y + 4 = 0 and 5x – 2y + 5 = 0 are perpendicular to each other.
Angle made by the line with the positive direction of X-axis is given. Find the slope of the line.
45°
Determine whether the following point is collinear.
L(2, 5), M(3, 3), N(5, 1)
Find k, if R(1, –1), S (–2, k) and slope of line RS is –2.
Determine whether the given point is collinear.
\[P\left( 1, 2 \right), Q\left( 2, \frac{8}{5} \right), R\left( 3, \frac{6}{5} \right)\]
Find the slope of a line, correct of two decimals, whose inclination is 50°
Find the slope of a line passing through the given pair of points (2,5) and (-1,8)
Find the slope of a line passing through the given pair of points (3,7) and (5,13)
Find the slope of a line passing through the given pair of points (9,-2) and (-5,5)
Find the slope of a line passing through the point A (-2,1), B (0,3).
With out Pythagoras theorem, show that A(4, 4), B(3, 5) and C(-1, -1) are the vertices of a right angled.
Prove that A(4, 3), B(6, 4), C(5, 6) and D(3, 5) are the angular points of a square.
If A(6, 1), B(8, 2), C(9, 4) and D(7, 3) are the vertices of `square`ABCD, show that `square`ABCD is a parallelogram.
Solution:
Slope of line = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
∴ Slope of line AB = `(2 - 1)/(8 - 6) = square` .......(i)
∴ Slope of line BC = `(4 - 2)/(9 - 8) = square` .....(ii)
∴ Slope of line CD = `(3 - 4)/(7 - 9) = square` .....(iii)
∴ Slope of line DA = `(3 - 1)/(7 - 6) = square` .....(iv)
∴ Slope of line AB = `square` ......[From (i) and (iii)]
∴ line AB || line CD
∴ Slope of line BC = `square` ......[From (ii) and (iv)]
∴ line BC || line DA
Both the pairs of opposite sides of the quadrilateral are parallel.
∴ `square`ABCD is a parallelogram.
