हिंदी

From the equation 3Cu+8HNOA3⟶3Cu(NOA3)A2+4HA2O+2NO (Atomic mass Cu = 64, H = 1, N = 14,O = 16) Calculate the mass of copper needed to react with 63g of HNO3. - Chemistry

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प्रश्न

From the equation

\[\ce{3Cu + 8HNO3 -> 3Cu(NO3)2 + 4H2O + 2NO}\]

(Atomic mass Cu = 64, H = 1, N = 14,O = 16)

Calculate the mass of copper needed to react with 63g of HNO3.

संख्यात्मक

उत्तर

Mol. Mass of 8HNO3 = 8 × 63 = 504 g

For 504 g HNO3, Cu required is = 192 g

So, for 63g HNO3Cu required = `(192 xx 63)/504`

= 24g

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अध्याय 5: Mole concept and Stoichiometry - Miscellaneous Exercises [पृष्ठ ९५]

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सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 2 | पृष्ठ ९५
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