Question

Geometrical isomerism is not shown by

विकल्प

• \[\begin{array}{cc}
  \ce{CH3}\phantom{..}\\
  |\phantom{.....}\\
  \ce{CH3CH2C = C CH2CH3}\\
  \phantom{....}|\\
  \phantom{......}\ce{CH3}
  \end{array}\]

• \[\begin{array}{cc}
  \ce{C2H5 - C = C - CH2l}\\
  \phantom{.}|\phantom{....}|\phantom{.}\\
  \phantom{}\ce{H}\phantom{...}\ce{H}\phantom{}
  \end{array}\]

• CH₂ = C(Cl)CH₃ 

• CH₃ – CH = CH – CH = CH₂

Answer 1

CH₂ = C(Cl)CH₃  

Explanation:

The condition for geometrical isomerism is

\[\begin{array}{cc}
\phantom{.}\ce{a}\phantom{.........}\ce{a}\phantom{}\\
\phantom{.}\backslash\phantom{......}/\phantom{}\\
\phantom{}\ce{C = C}\phantom{}\\
\phantom{}/\phantom{......}\backslash\\
\phantom{.}\ce{b}\phantom{.........}\ce{b}\phantom{}\\
\end{array}\]

or

\[\begin{array}{cc}
\phantom{.}\ce{a}\phantom{.........}\ce{e}\phantom{}\\
\phantom{.}\backslash\phantom{......}/\phantom{}\\
\phantom{}\ce{C = C}\phantom{}\\
\phantom{}/\phantom{......}\backslash\\
\phantom{.}\ce{b}\phantom{.........}\ce{d}\phantom{}\\
\end{array}\]

CH₂ = C(Cl)CH₃ does not follow above mention condition.