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प्रश्न
Give a balanced equation for the lab. Preparation of ethylene. How is the gas collected?
उत्तर
- \[\ce{\underset{Ethyl alcohol}{C2H5OH} + \underset{conc}{H2SO4} ->[<160^\circ C] \underset{sulphate]}{\underset{[Ethyl hydrogen}{C2H5HSO4}} + H2O}\]
- \[\ce{\underset{sulphate]}{\underset{[Ethyl hydrogen}{C2H5HSO4}} ->[< 160^\circ C][Excess of H2SO4] \underset{[Ethene or Ethylene]}{C2H4} + H2SO4}\]
The gas is collected by downward displacement of water because it is
- Insoluble in water
- It is inflammable gas.
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संबंधित प्रश्न
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\[\ce{H2C = CH2 ->[alk.KMnO4]}\]
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\[\ce{H2C = CH2 + HBr}\] →
Give reasons:
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