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Give the empirical formula of C2H2 - Chemistry

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प्रश्न

Give the empirical formula of C2H2

एक पंक्ति में उत्तर

उत्तर

The empirical formula of C2H2 is CH.

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Empirical Formula of a Compound
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole Concept And Stoichiometry - Exercise 1 [पृष्ठ ११५]

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फ्रैंक Chemistry - Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept And Stoichiometry
Exercise 1 | Q 11.3 | पृष्ठ ११५
सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Exercise 5C | Q 3.3 | पृष्ठ ९०

संबंधित प्रश्न

Identify the term or substance based on the descriptions given below:

The property by virtue of which the compound has the same molecular formula but different structural formulae.


If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.


 Give the appropriate term defined by the statements given below : 
The formula that represents the simplest ratio of the various elements present in one molecule of the compound. 


The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place)  (H=1,C=12,O=16)


Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]


Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.


In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.

Deduce the simplest formula by answering the following questions:

  1. How many gram-atoms of magnesium are equal to 18g?
  2. How many gram-atoms of nitrogen are equal to 7g of nitrogen?
  3. Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.

Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon combines with 21.3 g of chlorine. Calculate the empirical formula of the compound.


A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; \[\ce{C}\] = 12; \[\ce{Cl}\] = 35.5)


Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.


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