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प्रश्न
Give two evidences for presence of formyl group in glucose.
उत्तर
- Glucose gets oxidized to a six-carbon monocarboxylic acid called gluconic acid on reaction with bromine water which is a mild oxidizing agent. Thus, the carbonyl group in glucose is in the form of formyl (–CHO).
- Hemiacetal group of glucopyranose structure is a potential aldehyde (formyl) group. It imparts reducing properties to glucose. Thus, glucose gives positive Tollen’s test or Fehling test.
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संबंधित प्रश्न
Write chemical reaction for following conversions
glucose into gluconic acid
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From the following identify an example of disaccharides.
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Match the Column I and Column II select the correct option.
| Column I | Column II | ||
| i. | Monosaccharides | a. | Stored energy in animals |
| ii. | Glycogen | b. | Polymer made from ß-glucose molecules |
| iii. | Cellulose | c. | Exoskeleton of arthropods |
| iv. | Chitin | d. | Building blocks of carbohydrates |
| e. | Plant hormone |
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Corn is immersed in boiling water. It is then cooled, and the solution becomes sweet. It is due to ______.
\[\ce{CH2OH - CO - (CHOH)4 - CH2OH}\] is an example of ______.
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