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Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg. - Chemistry

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प्रश्न

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

संख्यात्मक

उत्तर

Here,

p = 760 mm Hg

K= 4.27 × 105 mm Hg

According to Henry’s law,

p = KHx

`=> "x"  = "p"/"K"_"H"`

= `(760  "mm Hg")/(4.27xx10^(5)  "mm Hg")`

= 1.78 × 10-3

i.e., solubility in terms of mole fraction of methane in benzene = 1.78 × 10-3

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अध्याय 2: Solutions - Exercises [पृष्ठ ६१]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 2 Solutions
Exercises | Q 35 | पृष्ठ ६१

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