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How is the sign (+ or -) of power of a lens related to its divergent or convergent action? - Physics

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प्रश्न

How is the sign (+ or -) of power of a lens related to its divergent or convergent action?

संक्षेप में उत्तर

उत्तर

The sign of power depends on the direction in which a light ray is deviated by the lens. The power could be positive or negative. If a lens deviates a ray towards its centre (converges), the power is positive and if it deviates the ray away from its centre (diverges), the power is negative.

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अध्याय 5: Refraction through a Lens - Exercise 5 (C) 1 [पृष्ठ १२६]

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सेलिना Physics [English] Class 10 ICSE
अध्याय 5 Refraction through a Lens
Exercise 5 (C) 1 | Q 9 | पृष्ठ १२६

संबंधित प्रश्न

Define the power of a lens.


 A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.


(a) At what distance should the lens be held from the figure in order to view the squares distinctly with the maximum possible magnifying power?

(b) What is the magnification in this case?

(c) Is the magnification equal to the magnifying power in this case? Explain.


Consider two statements A and B given below:
A: real image is always inverted
B:  virtual image is always erect
Out of these two statements:


A diverging lens has focal length of 3 cm. Calculate the power. 


Two lenses A and B have focal lengths of +20 cm and, −10 cm, respectively.
(a) What is the nature of lens A and lens B?
(b) What is the power of lens A and lens B?
(c) What is the power of combination if lenses A and B are held close together?


Express the power (with sign) of a concave lens of focal length 20 cm.


Mohan obtained a sharp inverted image of a distant tree on the screen placed behind the lens. He then moved the screen and tried to look through the lens in the direction of the object. He would see: 

(1) a blurred image on the wall of the laboratory. 

(2) an erect image of the tree on the lens.

(3) no image as the screen has been removed 

(4) an inverted image of the tree at the focus of the lens.


A diverging lens of focal length 20 cm and a converging lens of focal length 30 cm are placed 15 cm apart with their principal axes coinciding. Where should an object be placed on the principal axis so that its image is formed at infinity?


Express nanometer (nm) in terms of Angstrom

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