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प्रश्न
How many three-digit numbers are divisible by 7?
विकल्प
112
114
128
110
MCQ
उत्तर
128
Explanation:-
We have an AP starting at 105 because it is the first three digit number divisible by 7.
AP will end at 994 because it is the last three digit number divisible by 7.
Therefore, we have an AP 105,112,119…994
First term, a = 105
Common difference, d = 112 - 105 = 7
Using formula an = a + (n - 1)d, to find nth term of arithmetic progression, we can say that
994 = 105 + (n - 1)(7)
⇒ 994 = 105 + (n - 1)(7)
⇒ 889 = 7(n - 1)
⇒ n - 1 = `889/7`
⇒ n = 127 + 1 =128
994 is the 128th term of AP. Therefore, there are 128 terms in AP. In other words, we can also say that there are 128 three digit numbers divisible by 7.
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