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How many ways can a team of 3 boys,2 girls and 1 transgender be selected from 5 boys, 4 girls and 2 transgenders? - Mathematics

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प्रश्न

How many ways can a team of 3 boys,2 girls and 1 transgender be selected from 5 boys, 4 girls and 2 transgenders?

योग

उत्तर

Number of boys = 5

Number of girls = 4

Number of transgender = 2

Number of ways of selecting 3 boys from 5 boys = 5c3

Number of ways of selecting 2 girls from 4 girls = 4C2

Number of ways of selecting one transgender from 2 transgenders = 2C1

Total number of ways of selection

= 5C3 × 4C2 × 2C1 

= `(5!)/(3!(5 - 3)!) xx (4!)/(2!(4 - 2)!) xx (2!)/(1!(2 - 1)!)`

= `(5!)/(3!  2!) xx (4!)/(2!  2!) xx (2!)/(1!  1!)`

= `(5 xx 4 xx 3!)/(3!  2!) xx (4 xx 3 xx 2!)/(2!  2!) xx 2`

= `(5 xx 4)/(2 xx 1) xx 4 xx 3`

= 5 × 4 × 2 × 3

= 120

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Combinations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.3 [पृष्ठ १८६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.3 | Q 9. (v) | पृष्ठ १८६

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