Advertisements
Advertisements
प्रश्न
How much more percent seats were won by X as compared to Y in Assembly Election in the state based on the data given below.
| Party | Won (out of 294) |
| X | 158 |
| Y | 105 |
| Z | 18 |
| W | 13 |
उत्तर
On the basis of above given table
The total number of seats won by party X = 158
The total number of seats won by party Y = 105
∴ Total number of seats in election = 294
∴ Percentage of seats won by party X = `158/294 xx 100` = 53.74%
∴ Percentage of seats won by party Y = `105/294 xx 100` = 35.71%
So, difference of percentage = (53.74 – 35.71)% = 18.03%
Hence, party X won 18.03% compared to party Y.
APPEARS IN
संबंधित प्रश्न
Express the following as percent: `3/4`
Find the value of 1% of Rs. 500
Find the value of the following:
15% of 2 minutes
In a camp, there were 500 soldiers. 60 more soldiers joined them. What percent of the earlier (original) number have joined the camp?
The population of a small locality was 4000 in 1979 and 4500 in 1981, By what percent had the population increase?
The price of an article increased from ₹ 16 to ₹ 20; find the percentage increase.
Anbu scored 436 marks out of 500 in his exams. What was the percentage he scored?
Rain forests are home to 90,000 of the 2,50,000 identified plant species in the world. What per cent of the world’s identified plant species are found in rain forests?
In a class of 50 students, 8 % were absent on one day. The number of students present on that day was ______.
What is 800% of 800?
