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प्रश्न
If 1P1 + 2. 2p2 + 3. 3p3 + ....... 15. 15P15 = qPr – s, 0 ≤ s ≤ 1, then q+sCr–s is equal to ______.
विकल्प
135
136
137
138
MCQ
रिक्त स्थान भरें
उत्तर
If 1P1 + 2. 2p2 + 3. 3p3 + ....... 15. 15P15 = qPr – s, 0 ≤ s ≤ 1, then q+sCr–s is equal to 136.
Explanation:
1P1 + 2. 2p2 + 3. 3p3 + ....... 15. 15P15
= 1! + 2.2! + 3.3! + .... + 15.15!
= 1! + ((3 – 1)2!) + ((4 – 1)3!) + ((16 – 1)15!)
= 1! + 3! – 2! + 4! – 3! + 5! – 4! + .... + 16! – 15!
= 16! + 1 – 2!
= 16! – 1! = qPr – s
⇒ q = r = 16 and s = 1
So, q+sCr–s = 17C15 = `(17 xx 16)/2` = 136
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