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प्रश्न
If `(a + b)/(am + bn)= (b + c)/(mb + nc )= (c + a)/(mc + na)` prove that each of theseccc `2/(m+n)`provided a + b + c ≠ 0
उत्तर
`(a + b)/(am + bn)= (b + c)/(mb + nc )= (c + a)/(mc + na)` `
`" sumof antecedents"/"sumof consequents"`
= `(a + b+b+c+c+a)/(am + bn +mb+ nc +mc+na)`
= `(2(a+b+c))/(m(a+b+c) =n (a+b+c))`
= `2/(m+n)`
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