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प्रश्न
If A, B, C, D are the angles of a cyclic quadrilateral, then cos A + cos B + cos C + cos D is equal to ______.
विकल्प
2(cos A + cos C)
2(cos A + cos B)
2(cos A + cos D)
0
MCQ
रिक्त स्थान भरें
उत्तर
If A, B, C, D are the angles of a cyclic quadrilateral, then cos A + cos B + cos C + cos D is equal to 0.
Explanation:
Given that, ABCD is a cyclic quadrilateral.
So, A + C = 180°
`\implies` A = 180° – C
`\implies` cos A = cos(180° – C) = – cos C
`\implies` cos A + cos C = 0 ...(i)
Similarly, cos B + cos D = 0 ...(ii)
Adding, cos A + cos B + cos C + cos D = 0
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Trigonometric Functions of Sum and Difference of Angles
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