Advertisements
Advertisements
प्रश्न
If a body of mass m is moving on a rough horizontal surface of coefficient of kinetic friction µ, the net resultant force exerted by surface on the body is ______.
विकल्प
mg `sqrt(1+mu^2)`
μmg
mg
mg `sqrt(1-mu^2)`
MCQ
रिक्त स्थान भरें
उत्तर
If a body of mass m is moving on a rough horizontal surface of coefficient of kinetic friction µ, the net resultant force exerted by surface on the body is `bb("mg" sqrt(1+mu^2))`.
Explanation:
The normal force and friction are the only resultant forces acting on the box.
fk = µ mg
T.R. = `sqrt("N"^2+"f"_"k"^2)`
= `sqrt(("mg")^2+(mu"mg")^2)`
= mg `sqrt(1+mu^2)`
shaalaa.com
Friction
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?