Question

If [abc] ≠ 0, then `(["a" + "b b" + "c c" + "a"])/(["b c a"])` = ____________.

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Answer 1

If [abc] ≠ 0, then `(["a" + "b b" + "c c" + "a"])/(["b c a"])` = 2.

Explanation:

We know that, [a + b b + c c + a] = 2 [a b c]

∴ `(["a" + "b b" + "c c" + "a"])/(["b c a"]) = (2["a b c"])/(["a b c"])` = 2