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प्रश्न
If astronomical telescope of length 1.53 m has magnifying power of magnitude 50, the values of fo and fe are ____________.
विकल्प
fo = 0.03 m, fe = 1.5 m
fo = 1.55 m, fe = -0.02 m
fo = 1.5 m, fe = -0.03 m
fo = 1.5 m, fe = 0.03 m
MCQ
रिक्त स्थान भरें
उत्तर
If astronomical telescope of length 1.53 m has magnifying power of magnitude 50, the values of fo and fe are fo = 1.5 m, fe = 0.03 m.
Explanation:
`"L" = "f"_"o" + "f"_"e" = 1.53 "m"` .....(i)
`abs("M.P") = "f"_"o"/"f"_"e" = 50`
`50 "f"_"e"+ "f"_"e" = 1.53`
`51 "f"_"e" = 1.53`
`therefore "f"_"e" = 0.03 "m" `
From equation (i),
`"f"_"o" = 1.5 "m"`
`therefore "f"_"o" = 1.5 "m and" "f"_"e" = 0.0.3 "m"`
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