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प्रश्न
`"If "\frac{\cos \alpha }{\cos \beta }=m\text{ and }\frac{\cos \alpha }{\sin \beta }=n " show that " (m^2 + n^2 ) cos^2 β = n^2`
योग
उत्तर
`LHS = (m^2 + n^2 ) cos^2 β`
`=( \cos ^{2}\alpha /\cos ^{2}\beta +\cos^{2}\alpha/\sin ^{2}\beta )\cos ^{2}\beta \text{}[ \because \ \ m=\frac{\cos \alpha }{\cos \beta} "and"n = cosalpha/sinbeta]`
`=(( \cos ^{2}\alpha \sin ^{2}\beta +\cos^{2}\alpha \cos ^{2}\beta)/( \cos ^{2}\beta \sin ^{2}beta))\cos ^{2}\beta`
`=\cos ^{2}\alpha ( \frac{1}{\cos ^{2}\beta \sin^{2}\beta ))\cos }^{2}\beta`
`=\cos ^{2}\alpha /\sin ^{2}\beta =( \frac{\cos\alpha }{\sin \beta })^{2}`
= n2 = RHS
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