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प्रश्न
If `cosA/3 = cosB/4 = 1/5, - π/2 < A < 0` and `- π/2 < B < 0`, then the value of 2 sin A + 4 sin B is ______.
विकल्प
4
– 2
– 4
0
MCQ
रिक्त स्थान भरें
उत्तर
If `cosA/3 = cosB/4 = 1/5, - π/2 < A < 0` and `- π/2 < B < 0`, then the value of 2 sin A + 4 sin B is – 4.
Explanation:
Given, cos A = `3/5` and cos B = `4/5`
∵ ∠A and ∠B lie on the IV quadrant.
∴ sin A = `-sqrt(1 - 9/25)` and sin B = `-sqrt(1 - 16/25)`
`\implies` sin A = `-4/5` and sin B = `-3/5`
Now, 2 sin A + 4 sin B = `2(-4/5) + 4(-3/5)`
= `-8/5 - 12/5`
= `-20/5`
= – 4
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