If f(x) = 1-x1+x then f(-x) is equal to: - Business Mathematics and Statistics

If f(x) = $\frac{1 - x}{1 + x}$ then f(-x) is equal to:

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$\frac{1}{f (x)}$

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Functions and Their Graphs

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अध्याय 5: Differential Calculus - Exercise 5.10 [पृष्ठ १२३]

अध्याय 5 Differential Calculus
Exercise 5.10 | Q 4 | पृष्ठ १२३

Determine whether the following function is odd or even?

f(x) = $\log (x^{2} + \sqrt{x^{2} + 1})$

Let f be defined by f(x) = x³ – kx² + 2x, x ∈ R. Find k, if ‘f’ is an odd function.

If f(x) = $(\frac{x + 1}{x - 1})$ , then prove that f(f(x)) = x.

For f(x) = $\frac{x - 1}{3 x + 1}$ , write the expressions of $f (\frac{1}{x}) and \frac{1}{f (x)}$

If f(x) = e^x and g(x) = log_ex then find (f + g)(1)

If f(x) = e^x and g(x) = log_ex then find (5g)(1).

If f(x) = x² – x + 1 then f(x + 1) is:

If f(x) = ${\begin{cases} x^{2} - 4 x if x \geq 2 \\ x + 2 if x < 2 \end{cases}$ , then f(5) is

f(x) = -5, for all x ∈ R is a:

If f(x) = x² and g(x) = 2x + 1 then (fg)(0) is: