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प्रश्न
If f(x) = `(e^(x^2) - cos x)/x^2`, for x ≠ 0 is continuous at x = 0, then value of (0) is ______.
विकल्प
`2/3`
`5/2`
1
`3/2`
MCQ
रिक्त स्थान भरें
उत्तर
If f(x) = `(e^(x^2) - cos x)/x^2`, for x ≠ 0 is continuous at x = 0, then value of (0) is `underlinebb(3/2)`.
Explanation:
f(x) = `(e^(x^2) - cos x)/x^2`
Since f(x) is continuous at x = 0
`implies` f(0) = `lim_(x rightarrow 0) ` f(x)
`implies` f(0) = `lim_(x rightarrow 0) ((e^(x^2) - 1) - (cosx - 1))/x^2`
`implies` f(0) = `lim_(x rightarrow 0) (e^(x^2) - 1)/x^2 - lim_(x rightarrow 0) (-2sin^2 x/2)/x^2`
`implies` f(0) = `1 + 2 lim_(x rightarrow 0) [(sin x/2)/(x/2)]^2 xx 1/4 = 1 + 2/4 = 3/2`
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