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प्रश्न
If θ is acute and `(cos^2θ)/(cot^2 θ - cos^2 θ)` = 3, then θ is equal to ______.
विकल्प
60°
30°
90°
None of these
MCQ
रिक्त स्थान भरें
उत्तर
If θ is acute and `(cos^2θ)/(cot^2 θ - cos^2 θ)` = 3, then θ is equal to 60°.
Explanation:
We have `(cos^2θ)/(cot^2 θ - cos^2 θ)` = 3
`\implies` cos2 θ = 3(cot2 θ – cos2 θ)
`\implies` cos2 θ = 3 cot2 θ – 3 cos2 θ
`\implies` 4 cos2 θ = 3 cot2 θ
`\implies` 4 cos2 θ = `(3 cos^2 θ)/(sin^2 θ)`
`\implies` sin2 θ = `3/4`
`\implies` sin θ = `sqrt(3)/2`
`\implies` θ = 60°
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Trigonometric Functions of Triple Angle
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