Question

If L = ${\displaystyle \underset{x\to \infty }{lim}\frac{x^2\sin \frac{1}{x}-x}{1-\left|x\right|}}$, then value of L is ______.

विकल्प

• 0.00

• 1.00

• 2.00

• 3.00

Answer 1

If L = ${\displaystyle \underset{x\to \infty }{lim}\frac{x^2\sin \frac{1}{x}-x}{1-\left|x\right|}}$, then value of L is 0.00.

Explanation:

L = ${\displaystyle \underset{x\to \infty }{lim}\frac{x^2\sin \frac{1}{x}-x}{1-\left|x\right|}}$

= ${\displaystyle \underset{x\to \infty }{lim}\frac{x(x\sin \frac{1}{x}-1)}{x(\frac{1}{x}-1)}}$

= 0